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in Physics by (91.2k points)
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A particle of mass `M` at rest dacays into two particle of masses `m_(1)` and `m_(2) `having non zero velocity . The radio of the de Broglie wavelength . The ratio of the de Broglie wavelengtgh of the particle `lambda , _(1) // lambda_(2)` is
A. `m_(1)//m_(2)`
B. `m_(2)//m_(1)`
C. `1.0`
D. ` sqrt(m_(1))//sqrt(m_(2))`

1 Answer

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by (93.6k points)
 
Best answer
Correct Answer - C
Appling conservation of linear momentum, intial momentum = final momentum
`0 = M_(1) NU_(1) - M_(2)NU_(2)rArr M_(1) NU_(1) M_(2)NU_(2)`
= `Now , (lambda_(1))/(lambda_(2)) = (h// M_(1) NU_(1))/((h// M_(2) NU_(2)) = 1`

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