Question

A proton has kinetic energy `E = 100 keV` which is equal to that of a photo is `lambda_(1)` . The ratio of `k_(2) // lambda_(1) ` is proportional to
A. `E^(2)`
B. `E^(1//2)`
C. `E^(-1)`
D. `E^(-1//2)`

Answer 1

Correct Answer - D
For photon,
`lambda_(2) = (hc)/(E )`…(i)
For proton , P = sqrt(2mE)`
`lambda_(1) = (h)/(P) = (h)/(sqrt(2mE)) ` …(ii)
`(lambda_(2))/( lambda_(1)) = (hc)/(E xx (h)/(sqrt(2mE))) prop E^(1//2)`