Correct Answer - C
The wavelength of spectrum is given by
`(1)/(lambda) = Rz^(2) ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2))) where R = (1.097 xx 10^(7))/(1 + (m)/(M))`
where m = mass of electron
M= mass of nucleus
For different `M` , R is `different and therefore `lambda` is different