Question

In 1 g of a solid, there are `5xx10^(21)` atoms. If one electrons is removed fron each of 0.01% atoms of the solid, find the charge gained by the solid (given that electronic charge is `1.6xx10^(19)C`).

Answer 1

To calculate charge, we will apply formula `Q="ne"`, for this , we must have number of electrons. Here, number of electrons is
`n=0.01% of 5xx10^(21)`
i.e. `n=(5xx10^(21)xx0.1)/(100)=5xx10^(21)xx10^(-4)=5xx10^(17)`
so, `Q=5xx10^(17)xx1.6xx10^(-19)=8xx10^(-2)=0.08C`.
Since electrons have been removed, charge will be positive i.e.
`Q=+0.08C`