Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
234 views
in Physics by (92.0k points)
closed
Two particle of masses in the ration 1:2 with charges in the ratio 1:1, are palced at rest in a uniform electric field. They are relesaded and allowed to move for the same time. The ratio of their kinetic energies will be finally
A. `2:1`
B. `8:1`
C. `4:1`
D. `1:4`

1 Answer

0 votes
by (92.8k points)
 
Best answer
Correct Answer - A
As charge on both particles is same. So electric force action on them will be same. Since the particles are allowed to move for the same time, their final momentun will be same. Because change in momintum = impulse = forcexxtime, so
`KE=(P^2)/(2m)` gives `KE prop (1)/(m)`
`(KE_(1))/(KE_(2))=(m_(2))/(m_(1))=2:1`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...