Question

Three charges are placed as shown in fig. the magnitude of `q_(1)` is `2.00mu C`, but its sign and the value of the charge `q_(3)` is `+4.00muC`, and the net force on `q_(3)` is entirely in the negative x-direction

As per the condition given in the problem, the sign of `q_(1)` and `q_(2)` will be
A. `(54)/(64)mu C`
B. `(27)/(32)mu C`
C. `(13)/(32)mu C`
D. `(13)/(64)mu C`

Answer 1

Correct Answer - A
The four possibel force diagrame are shown in fig. Only the last pocture can result in an electric field the negative x-direction
`q_(1)=-2.00(mu)C, q_(2)= +4.00(mu)C, and q_(2)gt0`

`E_(y)=0=(1)/(4 pi epsilon_(0)) (q_1)/((0.0400m)^(2)) sin theta -(1)/(4 pi epsilon_(0))(q_2)/((0.0300m)^(2)) cos theta`
`q_(2)=9/16 (sin theta)/(cos theta)=9/16 q_(1) (3//5)/(4//5)=(27)/(64) q_(1)=0.843mu C`
`F_(3)=q_(3)E_(x)=q_(3)(1)/(4 pi epsilon_(0))((q_(1))/(0.0016)(4)/(5)+(q_(2))/(0.0009)3/5)=56.25N`.