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The full scale deflection current of a galvanometer of resistance `1Omega` is `5 mA`. How will you convert it into a voltmeter of range of `V`?

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The full scale deflection current of a galvanometer of resistance `1Omega` is `5 mA`. How will you convert it into a voltmeter of range of `V`?
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Correct Answer - A
`V=i_g(G+R)`
`:. R=V/i_g-G=` series resistance connected with galvonometer
`=(5/(5xx10^-3))-1=999Omega`
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