Correct Answer - B
We see that that surface of two spherial cavities carries charges `q_(1), - q_(2)` respectively, and since the sphere A was not charged orginally, its sphereical surface must carry induced charges `(q_(1) + q_(2))`. Therefore, force acting on conductor A is `q_(3) (q_(1) + q_(2))//4 pi epsilon_(0) r^(2)`