Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
209 views
in Physics by (92.0k points)
closed
A point charge `q` is placed inside a conducting spherical shell of inner radius `2 R` and outer radius `3 R` at a distance of `R` from the center of the shell. Find the electric potential at the center of the shell.
A. `(1)/(4 pi epsilon_0) q/(2 R)`
B. `(1)/(4 pi epsilon_0) (4 q)/(3 R)`
C. `(1)/(4 pi epsilon_0) (5 q)/(6 R)`
D. `(1)/(4 pi epsilon_0) (2 q)/(3 R)`

1 Answer

0 votes
by (92.8k points)
 
Best answer
Correct Answer - c
`V = k q/(R) -(k q)/(2 R) + (kq)/(3 R) = (k q)/(R) [1 - (1)/(2) + (1)/(3)]`
=`(k 5q)/(6 R)`
(##BMS_V03_C03_E01_104_S01##).

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...