Let charge flow be `q`.
Now applying Kirchhoff`s voltage low, we get
`((20-q))/2-((30+q))/2+((30-q))/1=0`
or `-2q=-25` or `q=12.5 muC`
Charge on `C_(1)` is `q_(1)=30-12.5=17.5 muC`
Charge on `C_(2)` is `q_(2)=30+12.5=42.5 muC`
Charge on `C_(3)` is `q_(3)=20-12.5-12.5=7.5 muC`.