Question

100 cells each of emf 5V and internal resistance `1 Omega` are to be arranged to produce maximum current in a `25 Omega` resistance. Each row contains equal number of cells. Find the number of rows.

Answer 1

Total number of cells is
mn = 100. (i)
Current will be maximum when
`R =(nr)/(m) or 25 = (nxx1)/(m)`
n =25m (ii)
From Eqs. (i) and (ii) we get n = 50 and m =2.