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A cable of resistance `10 Omega` carries electric power from a generator producing `250 kW at 10,000 V`. The current in the cable is

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A cable of resistance `10 Omega` carries electric power from a generator producing `250 kW at 10,000 V`. The current in the cable is
A. `1000 A`
B. `250 A`
C. `100 A`
D. `25 A`
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Correct Answer - D
`P = VI or I = (P)/( V) = ( 250 xx 1000)/( 10000) A = 25 A`
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