Question

The electric field strength depends only on the x, y, and z coordinates according to the law `E = (a(xhati+yhatj+zhatk))/(x^2+y^2+z^2)^3//2`, where ` a = 280 Nm^2C^(-1)` is a constant. If the potential difference between (3,2,6) and (0,3,4) is `x^2`. What is the value of x.

Answer 1

`vecE=(avecr)/(r^(2))`
`V=(-a)/(r)`
`triangleV=(a)/(r_(2))-(a)/(r_(1))=(a)/(5)-(a)/(7)=(2a)/(35)=2xx(280)/(35)=16V=4^(2)`