Correct Answer - Image will be at `-(5R)/(6)` from near end towards source;
image will be at `-( R )/(2)` from remote end
Case I.
Applying mirror formula for remote part `(u=-(3R)/(2), f=-(R)/(2))`
`v=(uf)/(u-f)=(-3)/(4)R`
Now, consider reflection from the nearer part for nearer part
`u=(3R)/(4)-2R=-(5R)/(4)rArrv=(uf)/(u-f)=oo`
Reflection from remote part gives `v=-(2R)/(2)`
Thus, the Image will be at `-(5R)/(6)` from near end toward source image will be at `-(R)/(2)` from remote end.
![image](https://learnqa.s3.ap-south-1.amazonaws.com/images/16104067569081587201610406756.png)