Correct Answer - b.
Distance of first image `(I_(1))` formed after refraction from the plane surface of water is
`(10)/(4//3)=7.5cm`
from water surface `(d_(app)=(d_(actual))/(mu))`.
Now, distance of this image is `5+7.5=12.5cm` from the plane mirror. Therefore, distance of second image `(I_(2))` will also be equal to 12.5 cm from the mirror.