Question

The amount of gas produced after the treatment of `21.8` gm of (D) with `MeMgBr` is:
A. `3.2` gm
B. `32.0` gm
C. `1.6` gm
D. `1.06` gm

Answer 1

Correct Answer - C

(D) `overset(MeMgBr)rarr CH_(4)` +
(Molecular mass of (D) `= C_(15)H_(22)O = 218`)
1 mol of (D) (218 gm) `implies` 1 mol of `CH_(4) = 16` gm
`21.8` gm `implies (16xx21.8)/(218)=1.6 gm`