Correct Answer - b.
For initial diverging lens,
`(1)/(-F)=(mu-1)((2)/(-R))`
`rArr (1)/(F)=((mu-1)2)/(R)` (i)
For final combination: `(1)/(F) =(1)/(f_(1))+(1)/(f_(2))+(1)/(f_(3))`
`rArr (2(mu-1))/(R)=(mu-1)[-(1)/(R)]`
`+(mu_(liq)-1)(2)/(R)+(mu-1)[-(1)/(R)]`
`rArr mu=(mu_(liq)+1)/(2)=(3+1)/(2)=2`