Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
91 views
in Physics by (89.5k points)
closed by
The atomic mass of uranium `._(92)^(238)U` is `23.058 u`, that of throium` ._(90)^(234)Th` is `234.0436 u` and that of an alpha particle `._2^4He` is `4.006 u`, Determine the energy released when `alpha-decay` converts`._(92)^(238)U` into `._(92)^(238) U`. int `._(90)^(234)Th`.

1 Answer

0 votes
by (94.2k points)
selected by
 
Best answer
Since energy is released during the decay, the combined mass of the `._(90)^(234)Th` daughter nucleus and the `alpha`- particle is less than the mass of the `._(90)^(238)U` parent nucleus. The difference in mass is equivalent to the energy released. We will determine the that 1 u is equivalent to 931.5 MeV. The decay and the masses are shown below:
`{:(._(92)^(238)Uto._(90)^(234)Th" + x"._(2)^(4)He),("238.0508 "ubrace("234.0436 4.0026 u")_("238.0462 u")):}`
The decrease in mass is 238.0508 u-238.0462 u=0.0046u. Since 1 u is equivalent to `931.5 MeV`, the released energy is 4.3 MeV. When `alpha` - decay occurs the energy released appears as kinetic energy of the recoiling `._(90)^(234)Th` nucleus and the `alpha` -particles, except for a small portion carried away as a `gamma`-ray.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...