Correct Answer - d
Let the decay constant for the first and second processes be `lambda_(1)` and `lambda_(2)` and the effective decay constant for the comined process be `lambda`. Then,
`lambda_(1)=(log_(e) 2)/(t_(1)) , lambda_(2)=(log_(e) 2)/(t_(2))` and` lambda=(log_(e) 2)/(t)`
Now, the probability for decay through first process in a small time interval dt is `lambda_(1) dt` and the probability for decay through second process in the same time interval dt is `lambda_(2) dt` . The probability for decay by the combined process in the same time interval dt is `lambda_(1) dt + lambda_(2) dt`.
But this is also equal to `lambda dt`.
` :. lambda dt = lambda_(1) dt + lambda_(2) dt`
`:. lambda=lambda_(1) + lambda_(2)`
or `(log_(e) 2)/(t)=(log_(e) 2)/(t_(1))+ (log_(e) 2)/(t_(2))`
or `(1)/(t) =(1)/(t_(1))+(1)/(t_(2))` or `t=(t_(1)t_(2))/(t_(1) +t_(2))`.