Correct Answer - 4
The ratio of `Ni` and `O` atom in pure `NiO=1:1` ltbr Let `a` be the number of `Ni(II)` atom replaced by `Ni(III)` atom in oxide. ltbr. `:.` No. of `Ni(II)` atom present `=0.98-a`
`:. `Oxide is neutral in nature
` :.` Total charge on `Ni` atom`=` Charge on `O` atom
`2(0.98-a)+3a=2`
`1.96-2a+3a=2`
`a=2-1.96=0.04`
`:. %` of `Ni(III)` atom in oxide.
`=("No . of Ni" (III)" atom")/("Total no . of Ni atom")xx100`
`=(0.04)/(0.98)xx100~~4%`