Correct Answer - d
`alpha=q/m`, path of the particle will
be a helix of time period,
`T=(2pim)/(Bq)=(2pi)/(B_0alpha)`
The given time `t=pi/(B_0q)=T/2`
`:.` Coordinateof particle at time `t=T//2`
would be `(v_xT//2),0,-2r)`
Here, `r=(mv_0)/(B_0q)=(v_0)/(B_0alpha)`
`:.` The coordinate are `((v_0pi)/(B_0q),0,(-2v_0)/(B_0alpha))`