Question

What is the electric flux linked with closed surface?

A. `10^(11)N-m^(2)//C`
B. `10^(12)N-m^(2)//C`
C. `10^(10)N-m^(2)//C`
D. `8.86xx10^(13)N-m^(2)//C`

Answer 1

Correct Answer - b
Electric flux, `phi= (q)/(epsilon_(0))`
Where `q=` total charg e enclosed by closed surface
`phi= (1.25+7+1-0.4)/(epsilon_(0))`
`=(8.85C)/(8.85xx10^(-12)C^(2)N^(-1)m^(-2))`
`10^(12)N-m^(2)//C`