Correct Answer - (c,d)
If `theta=0^@` then due to magnetic force path is circular but due
to force `qE_0(uarr)q` will have accelerated motion along y-axis. So
combined path of q will be a helical
path with variable pitch so (a) and
(b) are wrong.
If `theta=10^@`, then dut to `v cos theta`, path
is circular and due to `qE_0` and v sin
`theta`, q has accelerated motion along
y-axis so combined path is a helical
path with variable pitch (C) is correct.
If `theta=90^@ then F_B=0` and due to `qE_0` motion is accelerated along
y-axis. (d)