Correct Answer - b
Net force on `-q` towards the centre,
`F=(2F_(1).sin theta)`
`=2.(KQ.q)/(d^(2)+d^(2))xx(R )/(sqrt(d^(2)+d^(2)))`
For parctice to move in circle
`F= m omega^(2)R`
`implies (2KQqr)/((d^(2)+R^(2)))m omega^(2)R`
`implies omega=sqrt((2KQq)/(m(d^(2)+R^(2))^(3//2)))`
`=sqrt((2 xx9 xx 10^(9) xx 10 xx 10 xx 10^(-6))/(90 xx 10^(-3) xx(3^(2) + 4^(2))^(3//2))) =400 rad//s`