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At `t = 0`, switch `S` is closed (shown in Fig.). After a long time, suddenly the inductance of the inductor is made `eta` times lesser `(L//eta)` tha

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At `t = 0`, switch `S` is closed (shown in Fig.). After a long time, suddenly the inductance of the inductor is made `eta` times lesser `(L//eta)` than its initial value. Find out current just after the operation.
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`i_(1) = (varepsilon)/(R ),L_(1) i_(1) = L_(2)i_(2) rArr i_(2) = (eta varepsilon)/(R )`
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