Question

If `epsilon_0` and `mu_o` are, respectively, the electric permittivity and magnetic permeability of free space, `epsilon` and `mu` the corresponding quantities in a medium, the index of refraction of the medium in terms of the above parameters is….

Answer 1

We know that the velocity of light in vacuum `c = (1)/(sqrtmu_(0)epsilon_(0))` and the velocity of light in a medium `nu = (1)/(sqrt(mu epsilon))*` Also, the refractive index
`n = ("Velocity of light in vacuum")/("Velocity of light in medium") = (c )/(nu)`
`= (1//sqrt(mu_(0)epsilon_(0)))/(1//sqrt(mu epsilon)) = (sqrt(mu epsilon))/(sqrt(mu_(0)epsilon_(0)))`