Question

The network shows in Fig is part of a complate circuit. If at a certain instant the current `(I)` is `5 A`, and is decreasing at a rate of `10^(5) A s^(-1)` then `V_(B) - V_(A) = - V`.

Answer 1

`V_(A) - IR + E - L (dI)/(dt) = V_(B)`
`rArr V_(A) - 5 xx 1 + 15 - 5 xx 10^(-3)(-10^(-3)) = V_(B)`
`rArr V_(B) - V_(A) = 15V`