Question

Two capacitors of capacitance `2 muF` and `3 muF` are joined in series. Outer plate first capacitor is at `1000` volt and outer plate of second capacitor is earthed (grounded). Now the potential on inner plate of each capacitor will be
A. `700` Volt
B. `200` Volt
C. `600` Volt
D. `400` Volt

Answer 1

Correct Answer - D
Equivalent capacitance `= (2 xx 3)/(2 + 3) = (6)/(5) muF`
Total charge by `Q = CV = (6)/(5) xx 100 = 1200 muC`
Potential `(V)` across `2 muF` is
`V = (Q)/(C ) = (1200)/(2) = 600 V`
`:.` Potential on internal plates `= 1000 - 600 = 400 V`