Question

A capacitor of capacity `C_(1)` is charged to the potential of `V_(0)`. On disconnecting with the battery, it is connected with a capacity `C_(2)` as shown in the adjoining figure. The ratio of energies before and after the connection of switch `S` will be

A. `(C_(1) + C_(2))//C_(1)`
B. `C_(1)//(C_(1) + C_(2))`
C. `C_(1)C_(2)`
D. `C_(1)//C_(2)`

Answer 1

Correct Answer - A
Energy `(U) = (q^(2))/(2C). Q` remains same so `U prop (1)/(U)`
`rArr (U_(Before))/(U_(After)) = (C_(1) + C_(2))/(C_(1))`