Question

In the given network capacitance, `C_(1) = 10muF, C_(2) = 5 muF` and `C_(3) = 4muF`. What is the resultant capacitance between `A` and `B`?

A. `2.2 muF`
B. `3.2 muF`
C. `1.2 muF`
D. `4.7 muF`

Answer 1

Correct Answer - B

`C = ((C_(1)+C_(2))xxC_(3))/((C_(1) + C_(2))+C_(3)) = ((5 + 10) xx 4)/(5 + 10 +4) = (60)/(19) = 3.2 muF`