Question

Find out work done by electirc field in shifting a point charge `(4sqrt(2))/(27)muC` from point `P` to `S` which are shown in the figure:

A. `(100)/(3)J`
B. `(200)/(3)J`
C. `100 J`
D. `200 J`

Answer 1

Correct Answer - A
Work done by electirc field:
`W = PE_(i) - PE_(f) = q[V_(i) - V_(f)]`
`= q[(kp cos 45^(@))/((1 xx 10^(-2))^(2)) - (kp cos 135^(@))/((2 xx 10^(-2))^(2))]`
Here, `q = (4sqrt(2))/(27) muC` and `p = 2 xx 10^(-6) C_(-m)`
`:.` Work done `= (100)/(3) J`