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In the previous problem, if O is the point on AD and `OO_(1)` is the perpendicular from the centre of the circle, `O_(-1), then OA//OD` will be
A. `1`
B. `gt1`
C. `lt1`
D. depands upon `vec(B)` and charge

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Correct Answer - A
O will be the midpoint of incident and point of emergence . Hence, OA=OB.

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