Question

The current growth in two L-R circuits (b) and (c) is as shown in Fig. Let `L_(1), L_(2), R_(1) and R_(2)` be the corresponding values in two circuits. Then

A. `R_(1) gt R_(2)`
B. `R_(1) = R_(2)`
C. `L_(1) gt L_(2)`
D. `L_(1) lt L_(2)`

Answer 1

Correct Answer - B::D
Steady state current for both teh circuits is same. Therefore,
`(V)/(R_1)=(V)/(R_2) or R_(1)=R_(2)`
Further `tau_(L_(1)) lt tau_(L_2)` (`tau_(L) = "time costant"`)
`(L_1)/(R_1) lt (LL_2)/(R_2) or L_(1) lt L_(2)` `(R_(1)=R_(2))`.

Comments

Can u pls explain why is time constant of 2nd circuit greater than first?