Question

The energy stored in the capacitor in the steady state is

A. `338 mu J`
B. `196 mu J`
C. `98 mu J`
D. `8 mu J`

Answer 1

Correct Answer - A
(a) `V_(A) + 3 xx 1 - 14 - 5 xx 3V_(B)`
`implies V_(A) - V_(B) = 26 V`
Energy stored in capacitor
`U = (1)/(2) CV^(2) = (1)/(2) xx (10^(-6)) xx (26)^(2) = 338 mu J`