Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
60 views
in Physics by (93.7k points)
closed by
When electric bulbs of same power, but different marked voltage are connected in series across the power line, their brightness will be :
A. proportional to their marked voltage
B. inversely proportional to their marked voltage
C. porportional to the square of their marked voltage
D. inversely porportional to the square of their marked voltage

1 Answer

0 votes
by (94.0k points)
selected by
 
Best answer
Correct Answer - C
(c ) Resistance of bulb `R = (V^(2))/(P)` , Where `V` is the marked voltage and `P` is the marked power `P`.is same for both As both bulbs are connceted in series, so current in both of them will be same. So Brightness `prop R prop V^(2)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...