Correct Answer - C
(c ) Thermal power in `A = P_(A) = ((2 i)/(3))^(2) 3R = (4)/(3) i^(2) R`
Theremal power in `B = P_(B) = ((i)/(3))^(2) 6R = (2)/(3) i^(2) R`
Thermal power in `C = PC = i^(2) R`
`implies P_(A) : P_(B) : P_(C) = (4)/(3) : (2)/(3) : 1 = 4 : 2 : 3`
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