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In a potentiometer experiment the balancing with a cell is at length 240 cm. On shunting the cell with a resistance of `2Omega`, the balancing length becomes 120 cm.The internal resistance of the cell is
A. `4 Omega`
B. `2 Omega`
C. `1 Omega`
D. `0.5 Omega`

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Correct Answer - B
(b) `r = R ((l_(1))/(l_(2)) - 1) = 2 ((240)/(120)) = 2 Omega`

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