Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
2.9k views
in Physics by (93.7k points)
closed by
A current `i` ampere flows in a circular arc of wire whose radius is `R`, which subtend an angle `3pi//2` radian at its centre. The magnetic induction `B` at the centre is
image
A. `mu_(0)I//R`
B. `mu_(0)I//2R`
C. `2mu_(0)I//R`
D. `3mu_(0)I//8R`

1 Answer

0 votes
by (94.0k points)
selected by
 
Best answer
Correct Answer - C
For a loop, magnetic induction at centre,
`B=(mu_(0))/(4pi)xx(2piI)/R`
When loop subtends angle `theta` at centre, then
`B=(mu_(0))/(4pi)xx(thetaI)/R`
In the given problem, `theta=3pi//2`
`:. B=(mu_(0))/(4pi)xx(3pi)/2xx 1/R=(3mu_(0)I)/(8R)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...