Correct Answer - C
For a loop, magnetic induction at centre,
`B=(mu_(0))/(4pi)xx(2piI)/R`
When loop subtends angle `theta` at centre, then
`B=(mu_(0))/(4pi)xx(thetaI)/R`
In the given problem, `theta=3pi//2`
`:. B=(mu_(0))/(4pi)xx(3pi)/2xx 1/R=(3mu_(0)I)/(8R)`