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A galvanometer has a coil of resistance `100 Omega` and gives a full-scale deflection for `30 mA` current. If it is to work as a voltmeter of `30 V` range, the resistance required to be added will be
A. `900 Omega`
B. `1800 Omega`
C. `500 Omega`
D. `1000 Omega`

1 Answer

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Best answer
Correct Answer - A
Required resistance `R = (V)/(i_(g)) - G`
`= (30)/(30xx10^(-3)) - 100 = 900 Omega`

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