Correct Answer - B
The magnetic field `(B)` at the centre of circular current carrying coil of radius `R` and current `I, B = (mu_(0) I)/(2R)`
Similarly, if current `= 2l`, then
Magnetic filed `= (mu_(0) 2 I)/(2R) = 2B`
So, reusltant magnetic field
`= sqrt(B^(2) + (2B)^(2)) = sqrt(5B^(2)) = sqrt((5B)`
`= (mu_(0) I sqrt(5))/(2R)`