A square loop `ABCD`, carrying a current `I_(2)` is placed near and coplanar with a long straight conductor `XY`, carrying a current `I_(1)` as shown in Figure. The net force on the loop will be
A. `(mu_(0) I_(1) I_(2))/(2pi)`
B. `(2mu_(0) I_(1) I_(2))/(3pi)`
C. `(mu_(0) I_(1) I_(2)L)/(2pi)`
D. `(2mu_(0) I_(1) I_(2)L)/(3pi)`