Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.6k views
in Physics by (93.7k points)
closed by
The pole strength of a bar magnet is 48 ampere-metre and the distance between its poles is `25cm`. The moment of the couple by which it can be placed at an angle of `30^(@)` with the uniform magnetic intensity of flux density `0.15 "newton"//"ampere-metre"` will be
A. `12 "newton-metre"`
B. `18 "newton-metre"`
C. `0.9 "newton-metre"`
D. none of these

1 Answer

0 votes
by (94.0k points)
selected by
 
Best answer
Correct Answer - C
`tau=MB sintheta=48xx25xx10^(-2)xx0.15xx1/2=0.9 Nxxm`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...