Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
76 views
in Physics by (93.7k points)
closed by
A bar magnet of length `10cm` and having the pole strength equal to `10^(-3)` weber is kept in a magnetic field having magnetic induction (B) equal to `4pixx10^(-3)` Tesla. It makes an angle of `30^(@)` with the direction of mwgnetic induction. The value of the torque acting on the magnet is
`(mu_(0)=4pixx10^(-7) weber//ampxxm)`
A. `2pixx10^(-7) Nxxm`
B. `2pixx10^(-5) Nxxm`
C. `0.5 Nxxm`
D. `0.5xx10^(2) Nxxm`

1 Answer

0 votes
by (94.0k points)
selected by
 
Best answer
Correct Answer - A
Torque `tau=MB_(H)sintheta`
`=0.1xx10^(-3)xx4pixx10^(-3)xxsin30^(@)=10^(-7)xx4pixx1/2`
`=2pixx10^(-7) Nxxm`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...