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A coil of wire of a certain radius has `600` turns and a self-inductance of `108 mH`. The self-inductance of a `2^(nd)` similar coil of `500` turns will be
A. `74 mh`
B. `75 mH`
C. `76 mH`
D. `77 mH`

1 Answer

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Best answer
Correct Answer - B
`(L_(B))/(L_(A))=((n_(b))/(n_(A)))^(2)impliesL_(B)=((500)/(600))^(2)xx108=75mH`

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