Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
12.5k views
in Mathematics by (40.8k points)

Solve the following pairs of linear equations by elimination method and the substitution method.

(i) x + y = 5 and 2x - 3y = 4

(ii) 3x + 4y = 10 and 2x - 2y = 2

(iii) 3x - 5y - 4 = 0 and 9x = 2y + 7

1 Answer

0 votes
by (45.0k points)
selected by
 
Best answer

(i) By elimination method :

By substitution method :

On substituting the value of y from eqn. (iii) in eqn. (ii),

x = 19/5

On substituting this value of x in eqn. (iii), we get

(ii) By elimination method :

(iii) By elimination method :

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...