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A step-down transformer is connected to main supply `200V` to operate a `6V`, 30W` bulb. The current in primary is
A. `3A`
B. `1.5A`
C. `0.3A`
D. `0.15A`

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Correct Answer - D
`V_(p)=200V,V_(s)=6V`
`P_(out)=V_(s)i_(s)implies30=6xxi_(s)impliesi_(s)=5A`
From `(V_(s))/(V_(p))=(i_(p))/(i_(s))implies(6)/(200)=(i_(p))/(5)impliesi_(p)=0.15A`

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