Question

As a rejult of change in the magnetic flux linked to the closed loop shown in the figure, an emf `V` volt is induced in the loop. The work done (joules) in taking a charge `Q` coulomb once along the loop is

A. `QV`
B. `zero`
C. `2QV`
D. `(QV)/(2)`

Answer 1

Correct Answer - A
Induced emf work done in taking a charge
`(Q "once along the loop")/("charge"Q)`
i.e., is `V=(W)/(Q)`
`impliesW=VQ`