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+1 vote
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in Physics by (93.7k points)
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In the circuit shown, `R` is a pure resistor, `L` is an inductor of negligible resistance (as compared to `R`) and `S` is a`100V,50 Hz AC` source of negligible resistance. With eigther key `k_(1)` alone or `k_(2)` alone closed, the current is `I_(0)`. if the source is changed to `100 V, 100 Hz`, the current with `k_(1)` alone closed and with `k_(2)` alone closed will be respectively
image
A. `I_(0),1/2I_(0)`
B. `2I_(0),1/2I_(0)`
C. `2I_(0),I_(0)`
D. `2I_(0),1/2I_(0)`

1 Answer

+1 vote
by (94.0k points)
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Best answer
Correct Answer - A
With change in frequency resistance will not change but inductive reactance is reduced to half.

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