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The correct order of magnetic moment (spin values in is .
(Atomic number `Mn=25,Fe=26,Co=27)`
(I) `[MnBr_(4)]^(2-)`(II)`[Fe(CN)_(6)]^(4-)` (III) `[CoBr_(4)]^(2-)` .
A. `IIgtIIIgtI`
B. `IgtIIgtIII`
C. `IIgtIgtIII`
D. `IgtIIIgtII`

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Correct Answer - D
`Mn^(2+),Fe^(2+)` and `Co^(2+)` has `3d^(5),3d^(6)` and `3d^(7)` configuration having `5,0` and 3 unpaired electrons respectively .

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