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A coil of `200Omega` resistance and `1.0H` inductance is conneted to an `AC` source of frequency `200//2pi Hz`. Phase angle between potential and current will be
A. `30^(@)`
B. `90^(@)`
C. `45^(@)`
D. `0^(@)`

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Correct Answer - C
`tan phi=(X_(L))/R=(2pivL)/R`
`=(2pixx200/(2pi)xx1)/200=1 implies phi=45^(@)`

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